document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665851>Question 665851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify 3 times the fourth root of 486 subtract 2 times the fourth root of 2 plus 3 times the fourth root of 32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414111 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find perfect root factors of the numbers under the root - in this case they have to be perfect fourth root factors.  486 is 6*81 and 81 = 3*3*3*3 so pull out the 3 and 3*4throot(486) becomes 6*4throot(6).<P><BR>\n" );
document.write( "32 is 2*16, and 16 is 2*2*2*2 so 3*4throot(32) = 3*2*4throot(2) = 6*4throot(2).<P><BR>\n" );
document.write( "Add like terms.<P><BR>\n" );
document.write( "6*4throot(6)+4*4throot(2)<BR>\n" );
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