document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665806>Question 665806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify the result if possible<BR>\n" );
document.write( "2x +7 over x+4 minus x+3 over x+4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414095 by </B><A HREF=/tutors/aboutme.mpl?userid=Shana-D77><B>Shana-D77(132)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shana-D77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shana-D77><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x +7 over x+4 minus x+3 over x+4<BR>\n" );
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document.write( "Since these two weird fractions have the same denominator, we can go ahead and just subtract the numberators:<BR>\n" );
document.write( "(2x+7)/(x+4) - (x+3)/(x+4) = <BR>\n" );
document.write( "We'll just be looking at the numberator below, then put the denominator back in:<BR>\n" );
document.write( "(2x + 7) - (x + 3)<BR>\n" );
document.write( "2x + 7 - x - 3 (distributed the \"-\" to the (x + 3))<BR>\n" );
document.write( "x + 4 (combined like terms)<BR>\n" );
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document.write( "So your fraction becomes (x + 4)/(x + 4)<BR>\n" );
document.write( "Anything divided by itself is equal to 1, so your fraction simplifies to 1. </SPAN>\n" );
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