document.write( "Question 665761: A 25- Liter solution of alcohol in water is 72% alcohol. How many liters of an 80% solution must be added if the final solution should be 75% alcohol?.
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Algebra.Com's Answer #414075 by mananth(16946)\"\" \"About 
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-------------- percent ---------------- Amount
\n" ); document.write( "Alcohol I 72 ---------------- 25 liters
\n" ); document.write( "Alcohol II 80 ---------------- x liters
\n" ); document.write( "Mixture 75 ---------------- 25 + x liters
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\n" ); document.write( "72*25+80x=75(25 +x)
\n" ); document.write( "1800+80x=1875+75x
\n" ); document.write( "80x-75x =-1800+1875
\n" ); document.write( "5 x = 75
\n" ); document.write( "/ 5
\n" ); document.write( "x = 15 liters Alcohol II
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\n" ); document.write( "m.ananth@hotmail.ca
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