document.write( "Question 665761: A 25- Liter solution of alcohol in water is 72% alcohol. How many liters of an 80% solution must be added if the final solution should be 75% alcohol?.
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Algebra.Com's Answer #414075 by mananth(16946)![]() ![]() You can put this solution on YOUR website! -------------- percent ---------------- Amount \n" ); document.write( "Alcohol I 72 ---------------- 25 liters \n" ); document.write( "Alcohol II 80 ---------------- x liters \n" ); document.write( "Mixture 75 ---------------- 25 + x liters \n" ); document.write( " \n" ); document.write( "72*25+80x=75(25 +x) \n" ); document.write( "1800+80x=1875+75x \n" ); document.write( "80x-75x =-1800+1875 \n" ); document.write( "5 x = 75 \n" ); document.write( "/ 5 \n" ); document.write( "x = 15 liters Alcohol II \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |