document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665718>Question 665718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this problem is solving systems of equations. i dont know if i did the first steps correctly. the problem is: \r<BR>\n" );
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document.write( "-6y+7y=2x+2(x-2)-2x+2 (my answer was y=2x)<BR>\n" );
document.write( "4(x+y)-x+y=-23 (my answer was 3x+5y=-23)\r<BR>\n" );
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document.write( "if what i did was correct, i am confused as to the next step, especially getting the first equation into an \"x+y\" form.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414045 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414045\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -6y+7y=2x+2(x-2)-2x+2 \r<BR>\n" );
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document.write( "+y= 2x+2x-4-2x+2<BR>\n" );
document.write( "y=2x-2\r<BR>\n" );
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document.write( "4(x+y)-x+y=-23 <BR>\n" );
document.write( "4x+4y-x+y=-23<BR>\n" );
document.write( "3x+5y=-23\r<BR>\n" );
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document.write( "substitute y in second equation\r<BR>\n" );
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document.write( "3x+5y=-23<BR>\n" );
document.write( "3x+5(2x-2)=-23<BR>\n" );
document.write( "3x+10x-10=-23<BR>\n" );
document.write( "13x=-13<BR>\n" );
document.write( "x=-1\r<BR>\n" );
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document.write( "plug x<BR>\n" );
document.write( "we get y = -4 </SPAN>\n" );
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