document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665693>Question 665693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A and B start at 7 a.m. from two towns 37.5 miles apart. A's rate of walking being twice B's. If they walk 5 hours before they meet. find their rates of walking. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414013 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let B's rate be x<BR>\n" );
document.write( "A's rate = 2x\r<BR>\n" );
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document.write( "They are waling towards each other. So their combined rate = 2x+x=3x\r<BR>\n" );
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document.write( "distance = 37.5 miles\r<BR>\n" );
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document.write( "time = 5\r<BR>\n" );
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document.write( "speed = distance / time\r<BR>\n" );
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document.write( "3x= 37.5/5\r<BR>\n" );
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document.write( "multiply equation by 5<BR>\n" );
document.write( "15x= 37.5 <BR>\n" );
document.write( "/15<BR>\n" );
document.write( "x= 37.5/15<BR>\n" );
document.write( "x= 2.5 mph\r<BR>\n" );
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document.write( "B's walking rate = 2.5 mph<BR>\n" );
document.write( "A's walking rate = 2.5*2 = 5 mph\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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