document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665679>Question 665679</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the problem is \r<BR>\n" );
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document.write( "1/5x+1/5y=1<BR>\n" );
document.write( "x-y=1\r<BR>\n" );
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document.write( "i multiplied the top equation by 5 to eliminate the fractions and got:\r<BR>\n" );
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document.write( "x+y=5<BR>\n" );
document.write( "x-y=1\r<BR>\n" );
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document.write( "just not quite sure where to go from here to solve?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #414008 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=414008\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I love your first step as I hate fractions!<BR>\n" );
document.write( "Your system of equations are<BR>\n" );
document.write( "(1) x + y = 5<BR>\n" );
document.write( "(2) x - y = 1<BR>\n" );
document.write( "There are 2 or 3 ways to solve a pair of equations like these. I'll give you a couple, then which one you use depends on the simplicity of the given pair.<BR>\n" );
document.write( "The first is harder to understand by a beginner, but in this problem it is an obvious way to solve them. It is to add or subtract the equations from each other. Look at (1) and (2), see how the x terms and y terms are aligned under each other? The first technique is to recognized that if I literally ADD the left sides of (1) and (2) we get<BR>\n" );
document.write( "(3) x + y + x - y <BR>\n" );
document.write( "and if we add the right sides of (1) and (2) we get<BR>\n" );
document.write( "(4) 5 + 1<BR>\n" );
document.write( "Equating (3) and (4) we get<BR>\n" );
document.write( "(5) 2x + 0 = 6 or<BR>\n" );
document.write( "(6)  x = 3 and using (1) we get<BR>\n" );
document.write( "(7) 3 + y = 5 or<BR>\n" );
document.write( "(8) y = 2<BR>\n" );
document.write( "We'll show that (3,2) is the solution pair below, but now I want to show you the substitution method.<BR>\n" );
document.write( "Using substitution, we solve one of the given equations for one of the variables in terms of the other variable. Then substitute the resulting  expression into the second equation. Easier to do than explain so let's do it.<BR>\n" );
document.write( "Solve (2) for x and get<BR>\n" );
document.write( "(9) x = 1 + y<BR>\n" );
document.write( "Now put this expression for x into (1) giving us<BR>\n" );
document.write( "(10) 1 + y + y = 5 or simplifying<BR>\n" );
document.write( "(11) 2y = 4 or<BR>\n" );
document.write( "(12) y = 2 as before.<BR>\n" );
document.write( "Now put (12) into (9) and get<BR>\n" );
document.write( "(13) x = 1 + 2 or<BR>\n" );
document.write( "(14) x = 3<BR>\n" );
document.write( "Again the solution pair is (3,2).<BR>\n" );
document.write( "Is this correct?<BR>\n" );
document.write( "To check go back to the original (before you multiplied by 5) given equations. Is (3/5 + 2/5 = 1)?<BR>\n" );
document.write( "Is (5/5 = 1)?<BR>\n" );
document.write( "Is (1 = 1)? Yes<BR>\n" );
document.write( "Is (3 - 2 = 1)?<BR>\n" );
document.write( "Is (1 = 1)? Yes<BR>\n" );
document.write( "Answer: The solution pair is (3,2).<BR>\n" );
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