document.write( "Question 1364: Supose the diameter of a circle is 50 feet long and has a chord of 48 feet long. What is the distance from the center of the circle to the chord. \n" ); document.write( "
Algebra.Com's Answer #414 by khwang(438)\"\" \"About 
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\n" ); document.write( " As the diagram below,chord AB = 48 ft,center O,
\n" ); document.write( " OA (radius) = 50/2 = 25,M is the mid point of AB. So, AM = 24.
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\n" ); document.write( " A M B
\n" ); document.write( " ---------
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\n" ); document.write( " O\r
\n" ); document.write( "\n" ); document.write( " Since AM is perpendicular to AB, we have AO^2 = AM^2 + OM^2,
\n" ); document.write( " so OM^2 = AO^2 - AM^2 = 25^2 - 24^2 = 625 - 576 =49\r
\n" ); document.write( "\n" ); document.write( " Hence,the distance from the center of the circle to the chord is 7 ft
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