document.write( "Question 665562: Car A can travel 250 miles in 3 hours less time than it takes car B to travel 440 miles. The rate of car B is 5 mph faster than that of car A. Find the rates of both cars.
\n" ); document.write( "I know the answer. I need the to know how to set up the equation.
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Algebra.Com's Answer #413930 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Car A can travel 250 miles in 3 hours less time than it takes car B to travel 440 miles.
\n" ); document.write( " The rate of car B is 5 mph faster than that of car A.
\n" ); document.write( " Find the rates of both cars.
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\n" ); document.write( "let s = rate of car A
\n" ); document.write( "then
\n" ); document.write( "(s+5) = rate of car B
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\n" ); document.write( "Write a time equation, time = dist/rate
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\n" ); document.write( "Car A time + 3 hrs = Car B time
\n" ); document.write( "\"250%2Fs\" + 3 = \"440%2F%28%28s%2B5%29%29\"
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\n" ); document.write( "That's how you set it up, if you can't complete it, let me know,
\n" ); document.write( " I will edit this to show the rest of the procedure
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