document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665465>Question 665465</A>: <I><SPAN STYLE=\"word-break: break-all;\">  one of the digits of a  2 digit no is 3 times the other digit.if you interchange the digits of this no it is found resulting is 2times the original no.what is the no?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413928 by </B><A HREF=/tutors/aboutme.mpl?userid=kevwill><B>kevwill(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kevwill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kevwill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the smaller digit be x and the larger digit be y.  From the problem statement we are given that y = 3x.  <BR>\n" );
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document.write( "The two-digit number is 10x + y, and reversing the digits gives 10y + x.  We are told that reversing the digits doubles the original number, so\r<BR>\n" );
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document.write( "10y + x = 2(10x + y)<BR>\n" );
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document.write( "Substituting 3x for y into this equation gives:<BR>\n" );
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document.write( "10(3x) + x = 2(10x + 3x)<BR>\n" );
document.write( "30x + x = 20x + 6x<BR>\n" );
document.write( "31x = 26x<BR>\n" );
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document.write( "There are no non-zero values for x which make this equation true, so there is no solution to this problem as stated.<BR>\n" );
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