document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=500395>Question 500395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the number of ways to arrange the letters in MINIMUMS  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413908 by </B><A HREF=/tutors/aboutme.mpl?userid=kevwill><B>kevwill(135)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kevwill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=kevwill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413908\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think the original solver overlooked the fact that there are duplicated letters in the word that reduce the number of distinct permutations.  There are 2 I's and 3 M's, so the actual number of different ways to arrange the letters in MINIMUMS is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%21%2F%282%213%21%29 ALIGN=MIDDLE  ALT=\"8%21%2F%282%213%21%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = (8*7*6*5*4*3*2*1)/((2*1)*(3*2*1)) = 3360}}}<BR>\n" );
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