document.write( "Question 665386: at 8 am two cars 315 km apart head toward each other. car a is 20 km/hour faster. at 3pm they meet up. how fast are they? \n" ); document.write( "
Algebra.Com's Answer #413830 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed of car B be x km/h \n" ); document.write( "speed of car A = x+20 km/h\r \n" ); document.write( "\n" ); document.write( "distance = 315 km\r \n" ); document.write( "\n" ); document.write( "time = 7 hours . 8am to 3 pm\r \n" ); document.write( "\n" ); document.write( "since they are travelling towards each other, add up the speeds.\r \n" ); document.write( "\n" ); document.write( "combined speed = x+x+20= 2x+20\r \n" ); document.write( "\n" ); document.write( "d= s * t\r \n" ); document.write( "\n" ); document.write( "315 = 7(2x+20)\r \n" ); document.write( "\n" ); document.write( "315 = 14x+140\r \n" ); document.write( "\n" ); document.write( "14x=315-140\r \n" ); document.write( "\n" ); document.write( "14x= 175 \n" ); document.write( "/14 \n" ); document.write( "x= 175/14\r \n" ); document.write( "\n" ); document.write( "x= 12.5 km/h speed of car B\r \n" ); document.write( "\n" ); document.write( "speed of car A = 12.5 + 20 = 32.5 km/h\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |