document.write( "Question 665383: Solve the following 3x-3/x+1<_ 2 \n" ); document.write( "
Algebra.Com's Answer #413811 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(3x-3)/(x+1) <= 2
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\n" ); document.write( "Factor:
\n" ); document.write( "[3(x-1)/(x+1)] <= 2
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\n" ); document.write( "x cannot be -1
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\n" ); document.write( "Solve the Equality:
\n" ); document.write( "(3x-3)/(x+1) = 2
\n" ); document.write( "3x-3 = 2x+2
\n" ); document.write( "x = 5
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\n" ); document.write( "Draw a number line and plot x = -1, x = 5
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\n" ); document.write( "Test the interval (-oo,-1)
\n" ); document.write( "[3(x-1)/(x+1)] <= 2
\n" ); document.write( "If x = -3 you get (3(-4))/(-2) = 6 < 2 False
\n" ); document.write( "so no solutions where -oo\n" ); document.write( "------------------------------------
\n" ); document.write( "Test -1< x <5:
\n" ); document.write( "[3(x-1)/(x+1)] <= 2
\n" ); document.write( "If x = 0 you get (3(-1))/(1) = -3 <=2 True,
\n" ); document.write( "so solution in the interval (-1,5]
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\n" ); document.write( "Test the interval (5,+oo)
\n" ); document.write( "[3(x-1)/(x+1)] <= 2
\n" ); document.write( "If x = 10 you get (3(9))/(11 = 27/11 = 2 5/11 <= 2 False,
\n" ); document.write( "so no solutions in (5,+oo)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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