document.write( "Question 7473: Craig is 24 years younger than his father. In 10 yrs, Craig's father will be three times as old as Craig will be. Find their ages now.\r
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\n" ); document.write( "I first came up with c=f-24 but.. i got stuck with 10yrs to show in the formula..
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Algebra.Com's Answer #4138 by bonster(299)\"\" \"About 
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We know that Craig is 24 years younger than his father.
\n" ); document.write( "That means we'll use \"X\" to represent his father's age and use \"X-24\" to represent Craig's age:\r
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\n" ); document.write( "\n" ); document.write( "Craig's father: X
\n" ); document.write( "Craig: X-24\r
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\n" ); document.write( "\n" ); document.write( "Now it says that \"...in 10 years\" so before I do anything else, I need to add 10 to both of their ages. \r
\n" ); document.write( "\n" ); document.write( "(x)+10=(x-24)+10\r
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\n" ); document.write( "\n" ); document.write( "\"...Craig's father will be three times as old as Craig WILL BE\"
\n" ); document.write( "Since Craig father willl be 3 times as old as Craig will be, we need to multiply 3 to whatever age Craig will be in 10 years...which is denoted as (x-24+10)\r
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\n" ); document.write( "\n" ); document.write( "(x)+10=(x-24+10)(3)
\n" ); document.write( "x+10=(x-14)3
\n" ); document.write( "x+10=3x-42\r
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\n" ); document.write( "\n" ); document.write( "Subtract x from both sides to isolate the 10:
\n" ); document.write( "(x+10)-x=(3x-42)-x
\n" ); document.write( "10=2x-42\r
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\n" ); document.write( "\n" ); document.write( "add 42 to both sides to isolate the 2x:
\n" ); document.write( "(10)+42=(2x-42)+42
\n" ); document.write( "52=2x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides by 2
\n" ); document.write( "\"52%2F2\"=\"%282x%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "26=x\r
\n" ); document.write( "\n" ); document.write( "If x=26 (craig's father's age), then x-24=26-24=2 (craig's age)\r
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\n" ); document.write( "\n" ); document.write( "Craig=2 years old
\n" ); document.write( "Craig's father=26 years old
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