document.write( "Question 665233: What is the minor axis vertices written in (x1y1),(x2y2) form? \r
\n" ); document.write( "\n" ); document.write( "(x+2)^2/4+(y+3)^2/16=1\r
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Algebra.Com's Answer #413728 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28x%2B2%29%5E2%2F4%2B%28y%2B3%29%5E2%2F16=1\"$ \r
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\n" ); document.write( "\n" ); document.write( "the major axis is $\"vertical\"$ (because $\"4\"$ is smaller than $\"16\"$ )\r
\n" ); document.write( "\n" ); document.write( "so, the $\"sqrt%2816%29+=4\"$ \r
\n" ); document.write( "\n" ); document.write( "the $\"center\"$ is at ( $\"-2\"$ , $\"-3\"$ ), so move over $\"4\"$ vertically on both sides, and those are the vertices\r
\n" ); document.write( "\n" ); document.write( "so ( $\"-2\"$ , $\"-3%2B4\"$ ) = ( $\"-2\"$ , $\"1\"$ )
\n" ); document.write( "and ( $\"-2\"$ , $\"-3-4\"$ ) = ( $\"-2\"$ , $\"-7\"$ )\r
\n" ); document.write( "\n" ); document.write( "you can do the same for the minor axis, just moving horizontally up and down by $\"2\"$ \r
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