document.write( "Question 665004: in my text book it is written that the expression $\"sqrt+7x\"$ is a linear polynomial with degree 1\r
\n" ); document.write( "\n" ); document.write( "but my doubt is that how is this possible
\n" ); document.write( " according to my doubt $\"sqrt+7x\"$ is not a linear polynomial as this expression is having a sqrt in the variable. if an expression is having sqrt then its power will be negative. according to the the definition of polynomials there shoud'nt be a negative integral exponent for variables. so $\"sqrt+7x\"$ is not a polynomial.if it is not a polynomial we cant call it as a linear polynomial.this is my statement\r
\n" ); document.write( "\n" ); document.write( "then how is that in the book(maths grade 8 oxford) it is mentioned $\"sqrt+7x\"$ is a linear polynomial with degree 1. pls explain me \n" ); document.write( "

Algebra.Com's Answer #413687 by KMST(5330) $\"\"$ $\"About$

You can put this solution on YOUR website!
Maybe there was a typo in your textbook.
\n" ); document.write( "I have seen errors in high school textbooks, and some online material has even more errors.
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\n" ); document.write( "To make the meaning clear, you need some brackets.
\n" ); document.write( "To write a square root on this website, you need to put whatever is inside that square root in brackets.
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\n" ); document.write( "sqrt(7x)= $\"sqrt%287x%29\"$ =(7x)^(1/2)=7^(1/2)x^(1/2) is not a linear polynomial with degree 1. The exponent on the variable $\"x\"$ is $\"1%2F2\"$ .
\n" ); document.write( "sqrt(7)x= $\"sqrt%287%29x\"$ is a linear polynomial with degree 1, because the square root only covers the $\"7\"$ , forming a $\"sqrt%287%29\"$ coefficient in front of the variable $\"x\"$ , and the variable's exponent is an implied 1. \n" ); document.write( "

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