document.write( "Question 664992: In the game of blackjack as played in casinos, the dealer has the advantage as most of the players do not play very well. As a result, the probability that the average player wins a hand is about 40%. An average player decides to play 10 hands. e. Assuming that this player has already lost the first 6 hands, what is the probability that he will win all remaining (4) hands? \n" ); document.write( "

Algebra.Com's Answer #413629 by stanbon(75887) $\"\"$ $\"About$

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): In the game of blackjack as played in casinos, the dealer has the advantage as most of the players do not play very well. As a result, the probability that the average player wins a hand is about 40%. An average player decides to play 10 hands. e. Assuming that this player has already lost the first 6 hands, what is the probability that he will win all remaining (4) hands?
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\n" ); document.write( "The results on each hand are independent.
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\n" ); document.write( "P(win 4 hands) = 0.4^4 = 0.0256
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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