document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=665057>Question 665057</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the measure of two supplementary angles if the measure of the larger angle is 20 more than the smaller angle. I have tried the way I would try it but the larger angle came out equaling less and I have no clue how to find the answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413627 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the measure of two supplementary angles if the measure of the larger angle is 20 more than the smaller angle<BR>\n" );
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document.write( "1st: x<BR>\n" );
document.write( "2nd: 180-x<BR>\n" );
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document.write( "Note: At this point you do not know which angle is larger.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "180-x = x +20<BR>\n" );
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document.write( "Note: Now you are saying 180-x is 20 larger than \"x\".<BR>\n" );
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document.write( "2x = 160<BR>\n" );
document.write( "1st: x = 80<BR>\n" );
document.write( "2nd: 180-x = 100<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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