document.write( "Question 664410: I have the answer I just need to make sure it is correct. Please confirm.
\n" ); document.write( "The length of a rectangle is 2 inches more than the width. If the length and width are each increased by 3 inches, the perimeter of the new rectangle will be 4 inches less than 8 times the width of the original rectangle. Find the demensions.\r
\n" ); document.write( "\n" ); document.write( "I have for the original rectangle: Width= 5in, lenght=7in
\n" ); document.write( "The new rectangle I have width=8in, lenght=10in, but I had originally had 12inches for the lenght of the new rectangle, but when i checked it with the primeter, it did not work out.
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Algebra.Com's Answer #413589 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
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\n" ); document.write( "length of the 'original' rectangle is 2 inches more than the width\"highlight%28x%29\"
\n" ); document.write( "width x
\n" ); document.write( "length (x+2)
\n" ); document.write( "If the length and width are each increased by 3 inches
\n" ); document.write( "New width: \"x%2B3\"
\n" ); document.write( "New length: \"%28x%2B5%29\"\r
\n" ); document.write( "\n" ); document.write( "Question states***
\n" ); document.write( " perimeter of the new rectangle will be 4 inches less than 8 times the width of the original rectangle
\n" ); document.write( "P = 2L + 2W = \"2%28x%2B5%29+%2B+2%28x%2B3%29+=++8x-4\"
\n" ); document.write( " 2x+ 10 + 2x + 6 = 8x-4
\n" ); document.write( " 20 = 4x
\n" ); document.write( " x = 5in, width of the original rectangle. length = 7in. Good work
\n" ); document.write( "Find the dimensions of the New Rectangle: width = 8in and length 10in. Good work.
\n" ); document.write( "and...
\n" ); document.write( "\"20in+%2B+16in+=+36in+=+8%2A5in+-+4in\"\r
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\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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