document.write( "Question 664912: Two cars start from the same place at the same time. After two hours, one car has traveled 30% farther than the other. If one car's speed is 20mph larger than the other car's speed, what are the speeds of the cars? Solve algebraically \n" ); document.write( "

Algebra.Com's Answer #413526 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"Distance+=+Speed+%2A+time\"$ time = 2
\n" ); document.write( "Let the distance of the slower car be d. let the speed of the slower car be s.
\n" ); document.write( "You are told the distance of the faster car is 1.3d and its speed is $\"s%2B20\"$
\n" ); document.write( "So
\n" ); document.write( " $\"d+=+2s\"$ remember this for use later
\n" ); document.write( " $\"1.3d+=+%28s%2B20%29%2A+2\"$
\n" ); document.write( " $\"1.3d+=+2s+%2B+40\"$ use substitution with the value of d above
\n" ); document.write( " $\"1.3%282s%29+=+2s+%2B+40\"$
\n" ); document.write( " $\"2.6s+=+2s+%2B+40\"$
\n" ); document.write( " $\"0.6s+=+40\"$
\n" ); document.write( " $\"s+=+66.667\"$ mph
\n" ); document.write( "The faster car is going 86.667 (speeding is not kewl)
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