document.write( "Question 664889: how can 6,300 be invested, one part at 6% and the remainder at 7%, so that the income will be the same on each investment? \n" ); document.write( "

Algebra.Com's Answer #413510 by vleith(2983) $\"\"$ $\"About$

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let x be the amount you invest at 6%. Then $\"6300+-+x\"$ is the amount invested at 7%
\n" ); document.write( "You are told the interest from both investments is the same. So
\n" ); document.write( " $\"x+%2A+0.06+=+%286300-x%29+%2A+0.07\"$
\n" ); document.write( " $\"0.06x+=+441+-+0.07x\"$
\n" ); document.write( " $\"0.13x+=+441\"$
\n" ); document.write( " $\"x+=+3392.31\"$
\n" ); document.write( "invest 3392.31 at 6% and 6300-3392.31 at 7% \n" ); document.write( "

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