document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=664415>Question 664415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to prove the identity (cscx-1)/(cscx+1)is equal to (cot^2x)/(csc^2x+2cscx+1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413493 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How to prove the identity (cscx-1)/(cscx+1)is equal to (cot^2x)/(csc^2x+2cscx+1)<BR>\n" );
document.write( "start with left side:<BR>\n" );
document.write( "(cscx-1)/(cscx+1)*(cscx+1)/(cscx+1)<BR>\n" );
document.write( "=csc^2x-1/(csc^2x+2cscx+1)<BR>\n" );
document.write( "=(1/sin^2x-1)/(csc^2x+2cscx+1)<BR>\n" );
document.write( "=(1-sin^2x/sin^x)/(csc^2x+2cscx+1)<BR>\n" );
document.write( "=(cot^2x)/(csc^2x+2cscx+1)<BR>\n" );
document.write( "verified: left side=right side<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );