document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=664543>Question 664543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I was hoping to find the answer to this problem as well as the work on how to solve it. It is a particularly important review question I want to have on hand to refer back to if I get another question like it in the future on homework etc. Thanks! \r<BR>\n" );
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document.write( "Solve the following system of equations for x and y:\r<BR>\n" );
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document.write( "1/2x + 3/2y = 3/8\r<BR>\n" );
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document.write( "9/x - 6/y = 15/12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413351 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the following system of equations for x and y:\r<BR>\n" );
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document.write( "1/2x + 3/2y = 3/8\r<BR>\n" );
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document.write( "9/x - 6/y = 15/12<BR>\n" );
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document.write( "1/2x + 3/2y = 3/8<BR>\n" );
document.write( "Do you mean (1/2)x + (3/2)y? or 1/(2x) + 3/(2y) ?<BR>\n" );
document.write( "I would assume the former, but the 2nd equations appears to have the variables in the denominator.<BR>\n" );
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