document.write( "Question 664451: What is the center and radius of (x-5)2 + (y+6)2 = 49? \n" ); document.write( "
Algebra.Com's Answer #413338 by MathLover1(20850)\"\" \"About 
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use the standard equation that has the form\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+h%29%5E2+%2B+%28y+-+k%29%5E2+=+r%5E2\" where \"h\" and \"k\" are the \"x\"- and \"y\"-coordinates of the \"center\" of the circle and \"r\" is the radius\r
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\n" ); document.write( "\n" ); document.write( "you are given:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%5E2+%2B+%28y%2B6%29%5E2+=+49\"\r
\n" ); document.write( "\n" ); document.write( "so, \"h=5\", \"k=-6\", and \"r=7\"\r
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