document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=663673>Question 663673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of equilateral triangle whose perimeter is 12 inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #413282 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=413282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Equilateral means all the sides are the same<BR>\n" );
document.write( "p = a+b+c or in this case 3s<BR>\n" );
document.write( "12 = 3s<BR>\n" );
document.write( "s = 4 in for each side<BR>\n" );
document.write( "...<BR>\n" );
document.write( "To  find the height, cut the triangle in half to create two right triangles.<BR>\n" );
document.write( "The bottom of one of the triangles is 4/2 = 2<BR>\n" );
document.write( "The hypotenuse of the right triangle is 4<BR>\n" );
document.write( "solve for the other side, is solving for height<BR>\n" );
document.write( "s^2 + 2^2 = 4^2<BR>\n" );
document.write( "Isolate s^2<BR>\n" );
document.write( "s^2 = 4^2 - 2^2<BR>\n" );
document.write( "s^2 = 16-4 = 12<BR>\n" );
document.write( "s^2 = 12<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28s%29+=+sqrt%2812%29 ALIGN=MIDDLE  ALT=\"sqrt%28s%29+=+sqrt%2812%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284%2A3%29 ALIGN=MIDDLE  ALT=\"sqrt%284%2A3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 2<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "...<BR>\n" );
document.write( "a = 1/2(b)(h)<BR>\n" );
document.write( "a = 1/2(4)(2<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "a = 2(2<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >)<BR>\n" );
document.write( "a = 4<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".....<BR>\n" );
document.write( "Alternatively,<BR>\n" );
document.write( "The area formula in an equilateral triangle is <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%28s%5E2sqrt%283%29%29%2F%284%29 ALIGN=MIDDLE  ALT=\"a=%28s%5E2sqrt%283%29%29%2F%284%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Plug in the side determined from the perimeter<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=%284%5E2sqrt%283%29%29%2F%284%29 ALIGN=MIDDLE  ALT=\"a=%284%5E2sqrt%283%29%29%2F%284%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Such that,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=4sqrt%283%29 ALIGN=MIDDLE  ALT=\"a=4sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".........................<BR>\n" );
document.write( "Delighted to help.<BR>\n" );
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