document.write( "Question 664161: a car traveled at an average rate of 65 miles per hour and then reduced its average rate ro 45 miles per hour for the rest of the trip . if the 180 mile trip took 3 hours, determine how long the car traveled at each rate?
\n" ); document.write( "what i came up with was 180-65=115/3 and got 38.33 and 180-45=135/3 = 45 but when i added the two they dont equal the same so im really lost
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Algebra.Com's Answer #413196 by MathTherapy(10552)\"\" \"About 
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a car traveled at an average rate of 65 miles per hour and then reduced its average rate ro 45 miles per hour for the rest of the trip . if the 180 mile trip took 3 hours, determine how long the car traveled at each rate?
\n" ); document.write( "what i came up with was 180-65=115/3 and got 38.33 and 180-45=135/3 = 45 but when i added the two they dont equal the same so im really lost\r
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\n" ); document.write( "\n" ); document.write( "It can’t be done that way!!\r
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\n" ); document.write( "\n" ); document.write( "Let time 1st part of trip took be T
\n" ); document.write( "Then 2nd part of trip took 3 – T
\n" ); document.write( "Distance traveled during 1st part of trip, plus distance traveled during 2nd part of trip, equals total distance traveled, OR
\n" ); document.write( "65(T) + 45(3 – T) = 180
\n" ); document.write( "65T + 135 – 45T = 180
\n" ); document.write( "65T – 45T = 180 – 135
\n" ); document.write( "20T = 45\r
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\n" ); document.write( "\n" ); document.write( "T, or time taken on 1st part of trip, or at 65 mph = \"45%2F20\", or \"highlight_green%282.25%29\" hours, or 2 hours, 15 minutes\r
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\n" ); document.write( "\n" ); document.write( "Time taken on 2nd part of trip, or at 45 mph = 3 – 2.25, or \"highlight_green%28.75%29\" hour, or 45 minutes\r
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\n" ); document.write( "\n" ); document.write( "See if you can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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