document.write( "Question 664161: a car traveled at an average rate of 65 miles per hour and then reduced its average rate ro 45 miles per hour for the rest of the trip . if the 180 mile trip took 3 hours, determine how long the car traveled at each rate?
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document.write( "what i came up with was 180-65=115/3 and got 38.33 and 180-45=135/3 = 45 but when i added the two they dont equal the same so im really lost \n" );
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Algebra.Com's Answer #413196 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! a car traveled at an average rate of 65 miles per hour and then reduced its average rate ro 45 miles per hour for the rest of the trip . if the 180 mile trip took 3 hours, determine how long the car traveled at each rate? \n" ); document.write( "what i came up with was 180-65=115/3 and got 38.33 and 180-45=135/3 = 45 but when i added the two they dont equal the same so im really lost\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It can’t be done that way!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let time 1st part of trip took be T \n" ); document.write( "Then 2nd part of trip took 3 – T \n" ); document.write( "Distance traveled during 1st part of trip, plus distance traveled during 2nd part of trip, equals total distance traveled, OR \n" ); document.write( "65(T) + 45(3 – T) = 180 \n" ); document.write( "65T + 135 – 45T = 180 \n" ); document.write( "65T – 45T = 180 – 135 \n" ); document.write( "20T = 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T, or time taken on 1st part of trip, or at 65 mph = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time taken on 2nd part of trip, or at 45 mph = 3 – 2.25, or \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "See if you can do the check!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com \n" ); document.write( " |