document.write( "Question 664130: Use the Gauss-Jordan method to solve the system of equations.
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Algebra.Com's Answer #413135 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The system\r
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\n" ); document.write( "\n" ); document.write( "x-y=2
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\n" ); document.write( "\n" ); document.write( "is the same as\r
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\n" ); document.write( "\n" ); document.write( "1x-1y+0z=2
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\n" ); document.write( "\n" ); document.write( "and that converts to this matrix\r
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document.write( "1	-1	0	2\r\n" );
document.write( "0	1	-1	0\r\n" );
document.write( "1	0	1	6\r\n" );
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\r
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\n" ); document.write( "\n" ); document.write( "Now perform row reduction \r
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document.write( "1	-1	0	2\r\n" );
document.write( "0	1	-1	0\r\n" );
document.write( "1	0	1	6\r\n" );
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document.write( "1	-1	0	2	\r\n" );
document.write( "0	1	-1	0	\r\n" );
document.write( "0	1	1	4	R3 + (-1)*R1\r\n" );
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document.write( "1	0	-1	2	R1 + (1)*R2\r\n" );
document.write( "0	1	-1	0	\r\n" );
document.write( "0	1	1	4	\r\n" );
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document.write( "1	0	-1	2	\r\n" );
document.write( "0	1	-1	0	\r\n" );
document.write( "0	0	2	4	R3 + (-1)*R2\r\n" );
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document.write( "1	0	-1	2	\r\n" );
document.write( "0	1	-1	0	\r\n" );
document.write( "0	0	1	2	0.5*R3\r\n" );
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document.write( "1	0	0	4	R1 + (1)*R3\r\n" );
document.write( "0	1	-1	0	\r\n" );
document.write( "0	0	1	2	\r\n" );
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document.write( "1	0	0	4	\r\n" );
document.write( "0	1	0	2	R2 + (1)*R3\r\n" );
document.write( "0	0	1	2	\r\n" );
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\n" ); document.write( "\n" ); document.write( "The right hand column has the values, 4, 2 and 2.\r
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\n" ); document.write( "\n" ); document.write( "So x = 4, y = 2, and z = 2 are the three solutions\r
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\n" ); document.write( "\n" ); document.write( "The solution as an ordered triple is therefore (4, 2, 2)
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