document.write( "Question 663913: You pick 5 apples from a grocery store owned by the professor. The probability of a randomly chosen apple being rotten is 0.518. Let X represent the number of apples that are NOT rotten. Find the probability of X=k in the table below.\r
\n" ); document.write( "\n" ); document.write( "k P(X = k)
\n" ); document.write( "0
\n" ); document.write( "1
\n" ); document.write( "2
\n" ); document.write( "3
\n" ); document.write( "4
\n" ); document.write( "5 \r
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\n" ); document.write( "\n" ); document.write( "I tried multiplying .482*0 then .482*1 all the way down the table. \n" ); document.write( "

Algebra.Com's Answer #413039 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Note: The probability of x successes in n trials is: 
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document.write( "P = nCx*  where p and q are the probabilities of success and failure respectively. 
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document.write( "In this case p = .482 & q(rotton) = .518  and n = 5  nCx = 
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document.write( "Let X represent the number of apples that are NOT rotten. 
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document.write( "P(X = 0) = 5C0(.482)^0(.518)^5
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document.write( "P(X = 1) = 5C1(.482)^1(.518)^4
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document.write( "P(X = 2) = 5C2(.482)^2(.518)^3
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document.write( "P(X = 3) = 5C3(.482)^3(.518)^2
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document.write( "P(X = 4) = 5C4(.482)^4(.518)^1
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document.write( "P(X = 5) = 5C5(.482)^5(.518)^0 \n" );
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