document.write( "Question 663895: From the top of a building, a projectile is shot 400 feet high with a velocity of 64 feet per second. Its height h after t seconds is given by h(t)= -16t squared +64t+400.\r
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Algebra.Com's Answer #413028 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "h(t)=\"+-16t%5E2+%2B64t%2B400+=+-16%28t+-2%29%5E2+%2B+64+%2B+400+=+-16%28t-2%29%5E2+%2B+464\"
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document.write( "h(t) = \"-16%28t-2%29%5E2+%2B+464\"  V(2,464)max,   464ft is the max height.
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document.write( " 0 = -16(t-2)^2 + 464
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document.write( "(t-2)^2 = 29
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document.write( " t = 2 ± sqrt(29) ||tossing out negative solution for unit measrure
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document.write( " t = 7.39 sec, time it takes to hit the ground  \r
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document.write( "Donations on my website are appreciated.  Thanks.  ewatrrr
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document.write( "http://math-is-magical.weebly.com/index.html
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