document.write( "Question 663755: If a boy tosses a coin twice, and if the last result is a tail, he throws a die
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document.write( " (a) How many possible final outcomes are there?
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document.write( " (b)what is the probability of getting a head, tail and a 6 in that order \n" );
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Algebra.Com's Answer #412930 by Edwin McCravy(20065) You can put this solution on YOUR website! If a boy tosses a coin twice, and if the last result is a tail, he throws a die \n" ); document.write( " (a) How many possible final outcomes are there? \n" ); document.write( " \r\n" ); document.write( "Outcome 1: H, H Probability = (1/2)(1/2) = 1/4\r\n" ); document.write( "Outcome 2: H, T, 1 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 3: H, T, 2 Probability = (1/2)(1/2)(1/6) = 1/24 \r\n" ); document.write( "Outcome 4: H, T, 3 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 5: H, T, 4 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 6: H, T, 5 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 7: H, T, 6 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 8: T, H Probability = (1/2)(1/2) = 1/4\r\n" ); document.write( "Outcome 9: T, T, 1 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 10: T, T, 2 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 11: T, T, 3 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 12: T, T, 4 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 13: T, T, 5 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "Outcome 14: H, T, 6 Probability = (1/2)(1/2)(1/6) = 1/24\r\n" ); document.write( "\r\n" ); document.write( "So there are 14 outcomes, but they are not all equally likely.\r\n" ); document.write( " \n" ); document.write( "(b)what is the probability of getting a head, tail and a 6 in that order \n" ); document.write( " \r\n" ); document.write( "That's the outcome I colored red above. That's\n" ); document.write( " |