document.write( "Question 662667: Ivan is three years older than his sister Mary. One-third of Ivan's age is two years less than one-half his sister's age one year ago. Find their age's now. \n" ); document.write( "
Algebra.Com's Answer #412892 by kevwill(135)\"\" \"About 
You can put this solution on YOUR website!
I think the original solver got this one wrong.
\n" ); document.write( "Let's let i = Ivan's age and m = Mary's age. Ivan is 3 years older than Mary, so
\n" ); document.write( "\"i+=+m+%2B+3\"
\n" ); document.write( "The next one is a little tricky. One third of Ivan's age is two years less than one half of his sister's age one year ago. So
\n" ); document.write( "\"i%2F3+=+%28m-1%29%2F2+-+2\"
\n" ); document.write( "To simplify the rest of the solution, let's multiply both sides of the above equation by 6:
\n" ); document.write( "\"6%2A%28i%2F3%29+=+%286%2A%28m-1%29%29%2F2+-+6%2A2\"
\n" ); document.write( "\"2%2Ai+=+%286%2Am+-+6%29%2F2+-12\"
\n" ); document.write( "\"2%2Ai+=+3%2Am+-+3+-+12\"
\n" ); document.write( "\"2%2Ai+=+3%2Am+-+15\"
\n" ); document.write( "Substituting m+3 for i (from the first equation) gives us
\n" ); document.write( "\"2%2A%28m%2B3%29+=+3%2Am+-+15\"
\n" ); document.write( "\"2%2Am+%2B+6+=+3%2Am+-+15\"
\n" ); document.write( "Subtract 2*m from both sides:
\n" ); document.write( "\"2%2Am+%2B+6+-+2%2Am+=+3%2Am+-+15+-+2%2Am\"
\n" ); document.write( "\"6+=+m+-+15\"
\n" ); document.write( "Add 15 to both sides:
\n" ); document.write( "\"6+%2B+15+=+m+-+15+%2B+15\"
\n" ); document.write( "\"21+=+m\"
\n" ); document.write( "So Mary is 21 and Ivan is 24.\r
\n" ); document.write( "\n" ); document.write( "We can check our answer by inserting our values for i and m into the original second equation:
\n" ); document.write( "\"24%2F3+=+%2821+-+1%29%2F2+-+2\"
\n" ); document.write( "\"8+=+20%2F2+-+2\"
\n" ); document.write( "\"8+=+10+-+2\"
\n" ); document.write( "\"8+=+8\"
\n" ); document.write( "So our calculations are correct.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );