document.write( "Question 662667: Ivan is three years older than his sister Mary. One-third of Ivan's age is two years less than one-half his sister's age one year ago. Find their age's now. \n" ); document.write( "
Algebra.Com's Answer #412892 by kevwill(135)![]() ![]() You can put this solution on YOUR website! I think the original solver got this one wrong. \n" ); document.write( "Let's let i = Ivan's age and m = Mary's age. Ivan is 3 years older than Mary, so \n" ); document.write( " \n" ); document.write( "The next one is a little tricky. One third of Ivan's age is two years less than one half of his sister's age one year ago. So \n" ); document.write( " \n" ); document.write( "To simplify the rest of the solution, let's multiply both sides of the above equation by 6: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substituting m+3 for i (from the first equation) gives us \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subtract 2*m from both sides: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Add 15 to both sides: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So Mary is 21 and Ivan is 24.\r \n" ); document.write( "\n" ); document.write( "We can check our answer by inserting our values for i and m into the original second equation: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So our calculations are correct.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |