document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=663655>Question 663655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please solve given equation   3log(base8)x=-2     in other words 3log8x= -2..... just reiterating the 8 is a small number meaning it is a base. I know the answer is x = 1/4 but i have no idea how its done. please help i have been trying to solve this for over an hour </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412888 by </B><A HREF=/tutors/aboutme.mpl?userid=lynnlo><B>lynnlo(4176)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lynnlo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> EXAMPLE YOU CAN STUDY:<BR>\n" );
document.write( "TO CALCULATE THE LOG 3,(BASE 8)DIVIDE THE RESULT BY<BR>\n" );
document.write( "THE LOG BASE8<BR>\n" );
document.write( "TO CALCULATE BASE3,LOG 9 YOU GET 0.954,DIVIDE THAT BY LOG3<BR>\n" );
document.write( "(ABOUT 0.477)TO GET 2.0<BR>\n" );
document.write( "SINCE 9 IS 3 SQUARED THE LOG BASE 3 OF 9 IS 2 </SPAN>\n" );
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