document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=663653>Question 663653</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy is b years old and his father is 6times as old as him. Find the fathers age. and also the sum of thier ages in y years time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412873 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b = 6b<BR>\n" );
document.write( "Father is 6b, without b, or boy's age, cannot determine father's exact age.<BR>\n" );
document.write( "But, if boy is say 10, then father is 6(10)=60<BR>\n" );
document.write( "b+y = 6b+y<BR>\n" );
document.write( "In y years, they both will have increased in age by y years.<BR>\n" );
document.write( "If, for example, we look in 12 years, then<BR>\n" );
document.write( "b+12=6b+12 and if, for example, boy was 10, then<BR>\n" );
document.write( "10+12=6(10)+12<BR>\n" );
document.write( "boy is 22 and father is 60+12= 72<BR>\n" );
document.write( "........................<BR>\n" );
document.write( "Delighted to help.<BR>\n" );
document.write( "-Reading Boosters<BR>\n" );
document.write( "Wanting for others what we want for ourselves. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );