document.write( "Question 663648: Please help me factor z^3 - iz^2 + 3iz + 3 into linear factors
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Algebra.Com's Answer #412867 by Edwin McCravy(20056)\"\" \"About 
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document.write( "z³ - iz² + 3iz + 3\r\n" );
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document.write( "Factor z² out of the first two terms\r\n" );
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document.write( "z²(z - i) + 3iz + 3\r\n" );
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document.write( "Now we'd like to be able to factor z - i out of the last two terms 3iz + 3,\r\n" );
document.write( "It looks hopeless but we have a magic trick.  Since 1 = -i² we can multiply \r\n" );
document.write( "the 3 by -i² since that equals 1 and will not change the value of the\r\n" );
document.write( "expression:\r\n" );
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document.write( "z²(z - i) + 3iz + 3(-i²)\r\n" );
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document.write( "z²(z - i) + 3iz - 3i²\r\n" );
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document.write( "Now we can factor +3i out of the last two terms:\r\n" );
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document.write( "z²(z - i) + 3i(z - i)\r\n" );
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document.write( "That did it, so now we can factor out (z - i)\r\n" );
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document.write( "(z - i)(z² + 3i)\r\n" );
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document.write( "Edwin
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