document.write( "Question 663506: A rectangle has a length that is 5 feet more than its width. The area of this rectangle is 84 square feet. What is the width and length of this rectangle? \n" ); document.write( "

Algebra.Com's Answer #412826 by fxa101(1) $\"\"$ $\"About$

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let x= length
\n" ); document.write( " y = width = x - 5\r
\n" ); document.write( "\n" ); document.write( "A= Area of Rectangle\r
\n" ); document.write( "\n" ); document.write( "Formula: Area of Rectangle = length x width\r
\n" ); document.write( "\n" ); document.write( "84 = (x)(x - 5)
\n" ); document.write( "84 = x2 - 5x\r
\n" ); document.write( "\n" ); document.write( "Transpose 84 to the other side and get:
\n" ); document.write( "x2 -5x-84 = 0\r
\n" ); document.write( "\n" ); document.write( "Factor or by using quadratic formula, and get:
\n" ); document.write( "(x-7) = 0 (x-12) = 0: Both gives correct answer but we will use x-12: \r
\n" ); document.write( "\n" ); document.write( "Therefore;
\n" ); document.write( "x = 12
\n" ); document.write( "and y = x-5 = 7\r
\n" ); document.write( "\n" ); document.write( "Checking:\r
\n" ); document.write( "\n" ); document.write( "Area = length x width
\n" ); document.write( " = (12 feet)(7 feet)
\n" ); document.write( " = 84 square feet\r
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