document.write( "Question 663499: the length of a rectangle is 7 inches less than two times the width. the perimeter of the rectangle is 221 inches. Find the length and the width if the rectangle. (P= 2l+2w)
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Algebra.Com's Answer #412819 by MathLover1(20849)\"\" \"About 
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the length \"L\" of a rectangle is \"7+in\" less than two times the width \"W\", we have\r
\n" ); document.write( "\n" ); document.write( "\"L=2W-7in\"....1\r
\n" ); document.write( "\n" ); document.write( " the perimeter of the rectangle is \"P=221in\" \r
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\n" ); document.write( "\n" ); document.write( "\"P=+2L%2B2W\".....plug in \"L=2W-7in\" and \"P=221in\" \r
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\n" ); document.write( "\n" ); document.write( "\"221in=+2%2A%282W-7in%29%2B2w\".....solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"221in=+4W-14in%2B2W\"\r
\n" ); document.write( "\n" ); document.write( "\"221in%2B14in=+6W\"\r
\n" ); document.write( "\n" ); document.write( "\"235in=+6W\"\r
\n" ); document.write( "\n" ); document.write( "\"235in%2F6=+W\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%2839.1666in=+W%29\"\r
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\n" ); document.write( "\n" ); document.write( "now find \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"L=2W-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=2%2A39.17in-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=78.3333in-7in\"\r
\n" ); document.write( "\n" ); document.write( "\"L=highlight%2871.3333in%29\"\r
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