document.write( "Question 663511: Fred invested $45,000 for one year, part 5% and part at 3%. if he earned a total of $1910 for the year, how much was invested at each rate?\r
\n" );
document.write( "\n" );
document.write( "Let x= \n" );
document.write( "
Algebra.Com's Answer #412805 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! x = $ at 5% \n" ); document.write( "y = $ at 3% \n" ); document.write( "x+y = 45000 \n" ); document.write( ".05x + .03y = 1910 \n" ); document.write( ".05(45000-y) + .03y = 1910 \n" ); document.write( "2250 - .05y + .03y = 1910 \n" ); document.write( "2250 - .02y = 1910 \n" ); document.write( "-.02y = -340 \n" ); document.write( "y = $17,000 at 3% \n" ); document.write( "x = 45000 - 17000 = $28,000 at 5% \n" ); document.write( "Proof \n" ); document.write( ".05(28000)+.03(17000) = 1400 + 510 = 1910 \n" ); document.write( ".................. \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " |