document.write( "Question 663511: Fred invested $45,000 for one year, part 5% and part at 3%. if he earned a total of $1910 for the year, how much was invested at each rate?\r
\n" ); document.write( "\n" ); document.write( "Let x=
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Algebra.Com's Answer #412805 by ReadingBoosters(3246)\"\" \"About 
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x = $ at 5%
\n" ); document.write( "y = $ at 3%
\n" ); document.write( "x+y = 45000
\n" ); document.write( ".05x + .03y = 1910
\n" ); document.write( ".05(45000-y) + .03y = 1910
\n" ); document.write( "2250 - .05y + .03y = 1910
\n" ); document.write( "2250 - .02y = 1910
\n" ); document.write( "-.02y = -340
\n" ); document.write( "y = $17,000 at 3%
\n" ); document.write( "x = 45000 - 17000 = $28,000 at 5%
\n" ); document.write( "Proof
\n" ); document.write( ".05(28000)+.03(17000) = 1400 + 510 = 1910
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\n" ); document.write( "Delighted to help.
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