document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=663452>Question 663452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4 inches greater than twice its width. If the length and width are both increased by 2 in., its area is increased by 48in.^2 What is the width of the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412779 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l = 2w + 4<BR>\n" );
document.write( "(l+2)(w+2)=area+48<BR>\n" );
document.write( "area = (l)(w)<BR>\n" );
document.write( "w(2w+4) = 2w^2 + 4w<BR>\n" );
document.write( "Using (l+2)(w+2)=area + 48<BR>\n" );
document.write( "(2w+4+2)(w+2) = 2w^2 + 4w + 48<BR>\n" );
document.write( "(2w+6)(w+2) = 2w^2 + 4w + 48<BR>\n" );
document.write( "2w^2 + 4w + 6w + 12 = 2w^2 + 4w + 48<BR>\n" );
document.write( "2w^2 + 10w + 12 = 2w^2 + 4w + 48<BR>\n" );
document.write( "2w^2 - 2w^2 + 10w - 4w =48 - 12<BR>\n" );
document.write( "6w = 36<BR>\n" );
document.write( "width = 6 in.<BR>\n" );
document.write( ".......................<BR>\n" );
document.write( "Delighted to help.<BR>\n" );
document.write( "-Reading Boosters<BR>\n" );
document.write( "Wanting for others what we want for ourselves. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );