document.write( "Question 663295: a pyrotechniccian plans two fireworks to explode explode together at the same height in the air. they travel at 220 f/s and 200 f/s. the second firework is luanched 0.s5 seconds before the other one. how many seconds after will both fire works explode? \n" ); document.write( "
Algebra.Com's Answer #412700 by vleith(2983)\"\" \"About 
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Let the time required for the faster firework to reach the correct height be t.
\n" ); document.write( "Then the time for the slower firework is \"t%2B0.5\"
\n" ); document.write( "You know that the height for both is the same. You also know that the distance to that distance is given by \"height+=+speed+%2A+time\"\r
\n" ); document.write( "\n" ); document.write( "You are told the speed for both fireworks.
\n" ); document.write( "So
\n" ); document.write( "\"SpeedOne+%2A+t+=+SpeedTwo+%2A+%28t+%2B0.5%29\"
\n" ); document.write( "\"220+%2A+t+=+200%28t%2B0.5%29\"
\n" ); document.write( "\"220t+=+200t+%2B+100\"
\n" ); document.write( "\"20t+=+100\"
\n" ); document.write( "\"t+=+5\"
\n" ); document.write( "So 5 seconds after the faster one gets fired, they will both explode at a height of 1100 feet.\r
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