document.write( "Question 662945: One year a couple invested a total of $10,000 in two projects. The first investment , a mini mall , made a 6% profit. The other profit investment, a skateboard park, made 12% profit. If their investments made $960 , how much invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #412623 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! x+y = 10000 \n" ); document.write( ".06(x) + .12(y) = 960 \n" ); document.write( "Substitute into the second equation \n" ); document.write( ".06(10000-y) + .12y = 960 \n" ); document.write( "600 - .06y + .12y = 960 \n" ); document.write( "600 + .06y = 960 \n" ); document.write( ".06y = 960 - 600 \n" ); document.write( ".06y = 360 \n" ); document.write( "y = $6,000 at 12% \n" ); document.write( "x = 10000 - 6000 = $4,000 at 6% \n" ); document.write( "Proof \n" ); document.write( ".06(4000) + .12(6000) \n" ); document.write( "240 + 720 = 960 \n" ); document.write( "......................... \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " |