document.write( "Question 662945: One year a couple invested a total of $10,000 in two projects. The first investment , a mini mall , made a 6% profit. The other profit investment, a skateboard park, made 12% profit. If their investments made $960 , how much invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #412623 by ReadingBoosters(3246)\"\" \"About 
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x+y = 10000
\n" ); document.write( ".06(x) + .12(y) = 960
\n" ); document.write( "Substitute into the second equation
\n" ); document.write( ".06(10000-y) + .12y = 960
\n" ); document.write( "600 - .06y + .12y = 960
\n" ); document.write( "600 + .06y = 960
\n" ); document.write( ".06y = 960 - 600
\n" ); document.write( ".06y = 360
\n" ); document.write( "y = $6,000 at 12%
\n" ); document.write( "x = 10000 - 6000 = $4,000 at 6%
\n" ); document.write( "Proof
\n" ); document.write( ".06(4000) + .12(6000)
\n" ); document.write( "240 + 720 = 960
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