document.write( "Question 663090: The length of a rectangle is three times its width.
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document.write( "If the perimeter of the rectangle is 56m , find its area. \n" );
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Algebra.Com's Answer #412619 by ReadingBoosters(3246)![]() ![]() ![]() You can put this solution on YOUR website! p = 56 = 2l+2w \n" ); document.write( "l = 3w \n" ); document.write( "Substitute length, l, into the perimeter, p, equation \n" ); document.write( "56 = 2(3w)+2w \n" ); document.write( "Distribute the 2 \n" ); document.write( "56 = 6w + 2w \n" ); document.write( "Combine like terms \n" ); document.write( "56 = 8w \n" ); document.write( "w = 7m is width \n" ); document.write( "l = 3w = 3(7) = 21m is length \n" ); document.write( "... \n" ); document.write( "area = lxw = 7(21) = 147m^2 \n" ); document.write( "......................... \n" ); document.write( "Delighted to help. \n" ); document.write( "-Reading Boosters \n" ); document.write( "Wanting for others what we want for ourselves. \n" ); document.write( " |