document.write( "Question 663090: The length of a rectangle is three times its width.
\n" ); document.write( "If the perimeter of the rectangle is 56m , find its area.
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Algebra.Com's Answer #412619 by ReadingBoosters(3246)\"\" \"About 
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p = 56 = 2l+2w
\n" ); document.write( "l = 3w
\n" ); document.write( "Substitute length, l, into the perimeter, p, equation
\n" ); document.write( "56 = 2(3w)+2w
\n" ); document.write( "Distribute the 2
\n" ); document.write( "56 = 6w + 2w
\n" ); document.write( "Combine like terms
\n" ); document.write( "56 = 8w
\n" ); document.write( "w = 7m is width
\n" ); document.write( "l = 3w = 3(7) = 21m is length
\n" ); document.write( "...
\n" ); document.write( "area = lxw = 7(21) = 147m^2
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\n" ); document.write( "Delighted to help.
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