document.write( "Question 663091: A person must burn 3,500 calories to lose one pound of weight.\r
\n" ); document.write( "\n" ); document.write( "a) Write an equation that represents the number of calories a person would have to burn daily to lose 4 pounds in two weeks.\r
\n" ); document.write( "\n" ); document.write( "b) How many calories would the person have to burn each day?
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Algebra.Com's Answer #412618 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
x = weight loss in lb
\n" ); document.write( "y = calories burned
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\n" ); document.write( "(a)
\n" ); document.write( "calories burned / 3500 cal/lb = lbs lost
\n" ); document.write( "x = y/3500 which is the same as y = 3500x
\n" ); document.write( "if x is 4, then
\n" ); document.write( "y =4(3500) = 14,000 calories to burn
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\n" ); document.write( "(b)
\n" ); document.write( "calories burned / 3500cal/lb)((2 weeks)/(14 days/2 weeks)) = lbs lost / day
\n" ); document.write( "..
\n" ); document.write( "x = (y/3500)(2/(14/2) which is the same as x=(y/3500)(14) or x=14y/3500
\n" ); document.write( "rearrange to solve for y
\n" ); document.write( "y = 3500x/14
\n" ); document.write( "if x = 4 pounds then
\n" ); document.write( "y = 4(3500)/14 = 1,000 lb/day
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\n" ); document.write( "Delighted to help.
\n" ); document.write( "-Reading Boosters
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