document.write( "Question 662424: Solve System of Equation using Matrix notation\r
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\n" ); document.write( "(Eq.2) 3x+2y+z = -1
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Algebra.Com's Answer #412577 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "2	-1	3	4\r\n" );
document.write( "3	2	1	-1\r\n" );
document.write( "-1	3	2	5\r\n" );
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document.write( "1	-0.5	1.5	2	0.5*R1\r\n" );
document.write( "3	2	1	-1\r\n" );
document.write( "-1	3	2	5\r\n" );
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	3.5	-3.5	-7	R2 - 3*R1\r\n" );
document.write( "-1	3	2	5\r\n" );
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	3.5	-3.5	-7\r\n" );
document.write( "0	2.5	3.5	7	R3 + R1\r\n" );
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	1	-1	-2	0.285714*R2\r\n" );
document.write( "0	2.5	3.5	7\r\n" );
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	1	-1	-2\r\n" );
document.write( "0	0	6	12	R3 - 2.5*R2\r\n" );
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	1	-1	-2\r\n" );
document.write( "0	0	1	2	(1/6)*R3\r\n" );
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\n" ); document.write( "\n" ); document.write( "The Matrix is now in reduced echelon form (ref) and it is upper triangular\r
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document.write( "1	-0.5	1.5	2\r\n" );
document.write( "0	1	0	0	R2 + R3\r\n" );
document.write( "0	0	1	2\r\n" );
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document.write( "1	-0.5	0	-1	R1 - 1.5*R3\r\n" );
document.write( "0	1	0	0\r\n" );
document.write( "0	0	1	2\r\n" );
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document.write( "1	0	0	-1	R1 + 0.5*R2\r\n" );
document.write( "0	1	0	0\r\n" );
document.write( "0	0	1	2\r\n" );
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\n" ); document.write( "\n" ); document.write( "The Matrix is now in reduced row echelon form (rref)\r
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\n" ); document.write( "\n" ); document.write( "So the answers are x = -1, y = 0 and z = 2\r
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\n" ); document.write( "\n" ); document.write( "The answer as an ordered triple is (-1, 0, 2) \n" ); document.write( "
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