document.write( "Question 662901: Nancy drives in traffic for 2 and 1/2 hours. After traffic dies down she travels another 4 and 1/2 hrs. at 42 mph. If the entire trip was 371 miles, how fast was she driving in traffic?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #412547 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Nancy drives in traffic for 2 and 1/2 hours. After traffic dies down she travels another 4 and 1/2 hrs. at 42 mph. If the entire trip was 371 miles, how fast was she driving in traffic?
\n" ); document.write( "-------
\n" ); document.write( "1st leg DATA:
\n" ); document.write( "time = 5/2 hrs ; rate = x mph ; distance = (5/2)x miles
\n" ); document.write( "-------
\n" ); document.write( "2nd leg DATA:
\n" ); document.write( "time = 9/2 hrs ; rate = 42 mph ; distance = (9/2)*42 = 189 miles
\n" ); document.write( "-------
\n" ); document.write( "Equation:
\n" ); document.write( "distance + distance = 371
\n" ); document.write( "(5/2)x + 189 = 371
\n" ); document.write( "-----
\n" ); document.write( "(5/2)x = 182
\n" ); document.write( "----
\n" ); document.write( "x = (2/5)182
\n" ); document.write( "---
\n" ); document.write( "x = 72.8 mph(rate of the 1st leg)
\n" ); document.write( "=========================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );