document.write( "Question 662795: An average score of 80 to 90 in a math class receives a B grade. A student has scores of 92, 66, 72 and 88 of four tests. Find the range of scores on the fifth test that will give the student a B for the course.
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Algebra.Com's Answer #412544 by KMST(5328)\"\" \"About 
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I interpret the wording as meaning that 80 and 90 are both a B.
\n" ); document.write( "I'll solve based on that.
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\n" ); document.write( "WITH ROUNDING:
\n" ); document.write( "If we are going to be realistic, we have to consider rounding.
\n" ); document.write( "I expect that an average of 79.5 would be rounded up to 80, and would be enough for a B.
\n" ); document.write( "I expect that an average of 90.5 would be rounded up to 91, and that would be enough for an A,
\n" ); document.write( "but any average of less than 90.5 (even a 90.4) would be a B.
\n" ); document.write( "So I am starting from
\n" ); document.write( "\"79.5%3C=average%3C90.5\"
\n" ); document.write( "I am assuming they calculate the average as the sum of all tests grades divided by the number of tests.
\n" ); document.write( "If the score in the last test is \"x\", the average will be
\n" ); document.write( "\"average=%2892%2B66%2B72%2B88%2Bx%29%2F5=%28318%2Bx%29%2F5\"
\n" ); document.write( "Now my equation is
\n" ); document.write( "\"79.5%3C=%28318%2Bx%29%2F5%3C90.5\"
\n" ); document.write( "Multiplying all sides of the signs times 5, we get an equivalent inequality
\n" ); document.write( "\"79.5%2A5%3C=318%2Bx%3C90.5%2A5\" --> \"397.5%3C=318%2Bx%3C452.5\"
\n" ); document.write( "Subtracting \"318\" from all sides of the signs, we an the equivalent inequality
\n" ); document.write( "\"397.5%3C=318%2Bx%3C452.5\" --> \"397.5-318%3C=318%2Bx-318%3C452.5-318\" --> \"79.5%3C=x%3C132\"
\n" ); document.write( "So there is no possibility of getting an A, and a score of \"highlight%2880%29\" in the fifth test is needed to get an A as the final grade.
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\n" ); document.write( "WITH ROUNDING:
\n" ); document.write( "If the average has to be exactly 80.0 for a B,
\n" ); document.write( "then \"80%3C=%28318%2Bx%29%2F5\" --> \"400%3C=318%2Bx\" --> \"82%3C=x\", and an \"highlight%2882%29\" in the fifth test is needed for a B.
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