document.write( "Question 662795: An average score of 80 to 90 in a math class receives a B grade. A student has scores of 92, 66, 72 and 88 of four tests. Find the range of scores on the fifth test that will give the student a B for the course.
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Algebra.Com's Answer #412544 by KMST(5328)![]() ![]() You can put this solution on YOUR website! I interpret the wording as meaning that 80 and 90 are both a B. \n" ); document.write( "I'll solve based on that. \n" ); document.write( " \n" ); document.write( "WITH ROUNDING: \n" ); document.write( "If we are going to be realistic, we have to consider rounding. \n" ); document.write( "I expect that an average of 79.5 would be rounded up to 80, and would be enough for a B. \n" ); document.write( "I expect that an average of 90.5 would be rounded up to 91, and that would be enough for an A, \n" ); document.write( "but any average of less than 90.5 (even a 90.4) would be a B. \n" ); document.write( "So I am starting from \n" ); document.write( " \n" ); document.write( "I am assuming they calculate the average as the sum of all tests grades divided by the number of tests. \n" ); document.write( "If the score in the last test is \n" ); document.write( " \n" ); document.write( "Now my equation is \n" ); document.write( " \n" ); document.write( "Multiplying all sides of the signs times 5, we get an equivalent inequality \n" ); document.write( " \n" ); document.write( "Subtracting \n" ); document.write( " \n" ); document.write( "So there is no possibility of getting an A, and a score of \n" ); document.write( " \n" ); document.write( "WITH ROUNDING: \n" ); document.write( "If the average has to be exactly 80.0 for a B, \n" ); document.write( "then |