document.write( "Question 662862: i can't get to the correct solution, please help me\r
\n" ); document.write( "\n" ); document.write( "d=square root then(2- 1/2)2nd power + ( -1-4/3) 2nd power\r
\n" ); document.write( "\n" ); document.write( "can u please show how to solve this equation, many thanks
\n" ); document.write( "

Algebra.Com's Answer #412522 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
d=square root then(2- 1/2)2nd power + ( -1-4/3) 2nd power
\n" ); document.write( "-----------
\n" ); document.write( "If you mean
\n" ); document.write( "\"d=sqrt%28%282-+1%2F2%29%5E2+%2B+%28-1+-4%2F3%29%5E2%29\"
\n" ); document.write( "\"d=sqrt%28%283%2F2%29%5E2+%2B+%28-7%2F3%29%5E2%29\"
\n" ); document.write( "\"d=sqrt%28%289%2F4%29+%2B+%2849%2F9%29%29\"
\n" ); document.write( "\"d=sqrt%28%2881%2F36%29+%2B+%28196%2F36%29%29\"
\n" ); document.write( "\"d=sqrt%28277%2F36%29\"
\n" ); document.write( "\"d+=+sqrt%28277%29%2F6\"
\n" ); document.write( "d =~ 2.77389
\n" ); document.write( "===================
\n" ); document.write( "PS Click the \"Show source\" to see how to enter square roots.
\n" ); document.write( "
\n" ); document.write( "
\n" );