document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=662834>Question 662834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that the width of a rectangle is three feet shorter than length and that the <BR>\n" );
document.write( "perimeter of the rectangle is 86 feet.\r<BR>\n" );
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document.write( " Suppose that the width of a rectangle is three feet shorter than length and that the <BR>\n" );
document.write( "perimeter of the rectangle is 86 feet.<BR>\n" );
document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.<BR>\n" );
document.write( "Answer:  <BR>\n" );
document.write( "b) Solve this linear equation algebraically to find the length of the rectangle. Find <BR>\n" );
document.write( "the width as well.<BR>\n" );
document.write( "Answer:  Length ______, Width ______<BR>\n" );
document.write( "Show your work here:<BR>\n" );
document.write( "c)      Using the same width from your answer on part b), find a new perimeter when <BR>\n" );
document.write( "the new length is five less than three times the width.<BR>\n" );
document.write( "        Answer:<BR>\n" );
document.write( "          Explain your work here in one or two sentences: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412504 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( " Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=86+ft ALIGN=MIDDLE  ALT=\"86+ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "a) Set up an equation for the perimeter involving only L, the length of the rectangle.<BR>\n" );
document.write( "Answer: \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=2L%2B2W ALIGN=MIDDLE  ALT=\"P=2L%2B2W\"   DISABLED_style= \"max-width:90%; height:auto;\" >....given that <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=L-3ft ALIGN=MIDDLE  ALT=\"W=L-3ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=2L%2B2%28L-3ft%29 ALIGN=MIDDLE  ALT=\"P=2L%2B2%28L-3ft%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=2L%2B2L-6ft ALIGN=MIDDLE  ALT=\"P=2L%2B2L-6ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=4L-6ft ALIGN=MIDDLE  ALT=\"P=4L-6ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "b) Solve this linear equation algebraically to find the length of the rectangle. Find the width as well.\r<BR>\n" );
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document.write( "Answer:  Length is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=23ft ALIGN=MIDDLE  ALT=\"23ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >, Width is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=20ft ALIGN=MIDDLE  ALT=\"20ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Show your work here:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=4L-6ft ALIGN=MIDDLE  ALT=\"P=4L-6ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >......plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=86+ft ALIGN=MIDDLE  ALT=\"P=86+ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=86+ft=4L-6ft ALIGN=MIDDLE  ALT=\"86+ft=4L-6ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=86+ft%2B6ft=4L ALIGN=MIDDLE  ALT=\"86+ft%2B6ft=4L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=92ft=4L ALIGN=MIDDLE  ALT=\"92ft=4L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=92ft%2F4=L ALIGN=MIDDLE  ALT=\"92ft%2F4=L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=23ft=L ALIGN=MIDDLE  ALT=\"23ft=L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=L-3ft ALIGN=MIDDLE  ALT=\"W=L-3ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >..plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L ALIGN=MIDDLE  ALT=\"L\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=23ft-3ft ALIGN=MIDDLE  ALT=\"W=23ft-3ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=20ft ALIGN=MIDDLE  ALT=\"W=20ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "c)      Using the same width from your answer on part b), find a new perimeter when the new length is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=five ALIGN=MIDDLE  ALT=\"five\"   DISABLED_style= \"max-width:90%; height:auto;\" ><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+less ALIGN=MIDDLE  ALT=\"+less\"   DISABLED_style= \"max-width:90%; height:auto;\" > than three times the width.\r<BR>\n" );
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document.write( "   Answer: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=W=20ft ALIGN=MIDDLE  ALT=\"W=20ft\"   DISABLED_style= \"max-width:90%; height:auto;\" > <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=3W-5ft ALIGN=MIDDLE  ALT=\"L=3W-5ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >...=>...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=3%2A20ft-5ft ALIGN=MIDDLE  ALT=\"L=3%2A20ft-5ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >=>...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=60ft-5ft ALIGN=MIDDLE  ALT=\"L=60ft-5ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >=>...<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=L=55ft ALIGN=MIDDLE  ALT=\"L=55ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=2%2A55ft%2B2%2A20ft ALIGN=MIDDLE  ALT=\"P=2%2A55ft%2B2%2A20ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=110ft%2B40ft ALIGN=MIDDLE  ALT=\"P=110ft%2B40ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P=150ft ALIGN=MIDDLE  ALT=\"P=150ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "          Explain your work here in one or two sentences: you do this part\r<BR>\n" );
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document.write( " </SPAN>\n" );
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