document.write( "Question 662746: use the matrix method to solve the system of linear equations: \r
\n" ); document.write( "\n" ); document.write( " x+ y- z= 0
\n" ); document.write( "3x- y+3z=-2
\n" ); document.write( " x+2y-3z=-1\r
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Algebra.Com's Answer #412494 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1     1    -1     0\r\n" );
document.write( "3    -1     3    -2\r\n" );
document.write( "1     2    -3    -1\r\n" );
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document.write( "1     1    -1     0\r\n" );
document.write( "0    -4     6    -2    R2 - 3R1\r\n" );
document.write( "1     2    -3    -1\r\n" );
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document.write( "1     1    -1     0\r\n" );
document.write( "0    -4     6    -2\r\n" );
document.write( "0     1    -2    -1   R3 - R1\r\n" );
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document.write( "1    1   -1     0\r\n" );
document.write( "0    1   -1.5   0.5  (1/4)*R2\r\n" );
document.write( "0    1   -2     1\r\n" );
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document.write( "1    1   -1      0\r\n" );
document.write( "0    1   -1.5    0.5\r\n" );
document.write( "0    0   -0.5   -1.5   R3 - R2\r\n" );
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document.write( "1    1   -1      0\r\n" );
document.write( "0    1   -1.5    0.5\r\n" );
document.write( "0    0    1      3    -2*R3\r\n" );
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document.write( "1    1   -1      0\r\n" );
document.write( "0    1   -1.5    0.5\r\n" );
document.write( "0    0    1      3    -2*R3\r\n" );
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document.write( "1     1    -1     0\r\n" );
document.write( "0     1     0     5   R2 + 1.5*R3\r\n" );
document.write( "0     0     1     3\r\n" );
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document.write( "1     1     0     3   R1 + R3\r\n" );
document.write( "0     1     0     5\r\n" );
document.write( "0     0     1     3\r\n" );
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document.write( "1     0     0    -2   R1 - R2\r\n" );
document.write( "0     1     0     5\r\n" );
document.write( "0     0     1     3\r\n" );
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\n" ); document.write( "\n" ); document.write( "So x = -2, y = 5 and z = 3 \n" ); document.write( "
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