document.write( "Question 662785: how do i solve?
\n" ); document.write( "The product of 5 and 2 less than triple a number equals the product of 7 and 8 more than twice the number. What is the number?
\n" ); document.write( "I did this:\r
\n" ); document.write( "\n" ); document.write( "5(2)-3n=7(8)+2n
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Algebra.Com's Answer #412477 by DrBeeee(684)\"\" \"About 
You can put this solution on YOUR website!
You did a no-no.
\n" ); document.write( "The first expression should be
\n" ); document.write( "(1) 5*(3*n - 2)
\n" ); document.write( "The second should be
\n" ); document.write( "(2) 7*(8 + 2*n)
\n" ); document.write( "See the difference and why?
\n" ); document.write( "In the first you have the product of 5 AND (something) or 5 times (something), that (something) is \"2 less than 3 times n\" or (3*n - 3), giving you
\n" ); document.write( "(1) 5*(3*n - 2)
\n" ); document.write( "The same applies to the second expression - 7 times \"something\", which is now (2*n + 8), giving you (2).
\n" ); document.write( "The expressions (1) and (2) are equal so we get
\n" ); document.write( "(3) 5*(3*n-2) = 7*(2*n+8)
\n" ); document.write( "Multiplying (3) out you get
\n" ); document.write( "(4) 15*n - 10 = 14*n + 56
\n" ); document.write( "Simplify (4) to get
\n" ); document.write( "(5) n = 66
\n" ); document.write( "Is this correct? Let's check with (3)
\n" ); document.write( "Is (5*(3*66-2) = 7*(2*66+8))?
\n" ); document.write( "Is (5*(198-2) = 7*(132+8))?
\n" ); document.write( "Is (5*196 = 7*140)?
\n" ); document.write( "Is (980 = 980)? Yes
\n" ); document.write( "Answer: the number is 66.
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