document.write( "Question 662785: how do i solve?
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document.write( "The product of 5 and 2 less than triple a number equals the product of 7 and 8 more than twice the number. What is the number?
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document.write( "I did this:\r
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document.write( "5(2)-3n=7(8)+2n
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Algebra.Com's Answer #412477 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! You did a no-no. \n" ); document.write( "The first expression should be \n" ); document.write( "(1) 5*(3*n - 2) \n" ); document.write( "The second should be \n" ); document.write( "(2) 7*(8 + 2*n) \n" ); document.write( "See the difference and why? \n" ); document.write( "In the first you have the product of 5 AND (something) or 5 times (something), that (something) is \"2 less than 3 times n\" or (3*n - 3), giving you \n" ); document.write( "(1) 5*(3*n - 2) \n" ); document.write( "The same applies to the second expression - 7 times \"something\", which is now (2*n + 8), giving you (2). \n" ); document.write( "The expressions (1) and (2) are equal so we get \n" ); document.write( "(3) 5*(3*n-2) = 7*(2*n+8) \n" ); document.write( "Multiplying (3) out you get \n" ); document.write( "(4) 15*n - 10 = 14*n + 56 \n" ); document.write( "Simplify (4) to get \n" ); document.write( "(5) n = 66 \n" ); document.write( "Is this correct? Let's check with (3) \n" ); document.write( "Is (5*(3*66-2) = 7*(2*66+8))? \n" ); document.write( "Is (5*(198-2) = 7*(132+8))? \n" ); document.write( "Is (5*196 = 7*140)? \n" ); document.write( "Is (980 = 980)? Yes \n" ); document.write( "Answer: the number is 66. \n" ); document.write( " |