document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=662660>Question 662660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 7. If three times the square of the first number is added to twice the square of the second number, the sum is 59. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412425 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=7<BR>\n" );
document.write( "3x^2 + 2y^2 = 59<BR>\n" );
document.write( "3(-y+7)(-y+7) + 2y^2 = 59<BR>\n" );
document.write( "3(y^2-7y-7y+49) + 2y^2 = 59<BR>\n" );
document.write( "3y^2 - 42y + 147 + 2y^2 = 59<BR>\n" );
document.write( "5y^2 - 42y + 88 = 0<BR>\n" );
document.write( "(5y-22)(y-4) = 0<BR>\n" );
document.write( "5y-22=0 so y = 22/5<BR>\n" );
document.write( "y-4=0 so y = 4<BR>\n" );
document.write( "Two possibilities<BR>\n" );
document.write( "if y = 4, x = 7-4=3<BR>\n" );
document.write( "if y = 22/5, x = 7 - 22/5 = 13/5<BR>\n" );
document.write( "...........................<BR>\n" );
document.write( "Delighted to help.<BR>\n" );
document.write( "-Reading Boosters<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );