document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=662657>Question 662657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 1m less than four times the width. if the area of the rectangle is 33m^2. find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #412423 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=412423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l = 4w- 1<BR>\n" );
document.write( "a = 33 = lw<BR>\n" );
document.write( "substituting l<BR>\n" );
document.write( "33 = (4w-1)w<BR>\n" );
document.write( "33 = 4w^2-w<BR>\n" );
document.write( "4w^2 - w - 33 = 0<BR>\n" );
document.write( "(4w+11)(w-3) = 0<BR>\n" );
document.write( "4w+11=0 so w=-11/4 width cannot be negative<BR>\n" );
document.write( "w-3=0 so w=3 yes<BR>\n" );
document.write( "width = 3m<BR>\n" );
document.write( "length = 4(3)-1=11m<BR>\n" );
document.write( ".........................<BR>\n" );
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document.write( "-Reading Boosters<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );